# Python - How To List Intersection in Python

ID : 314

viewed : 64

Tags : PythonPython List  90

In this tutorial, we will discuss several methods to get the intersection between two in Python.

Intersection (or AND) is basically an operation specifically designed for . It works by selecting the common elements in two sets. For exmaple,

``setA = {1, 2, 3, 4, 5} setB = {0, 2, 4, 6}  print(setA & setB) ``

Output:

``{2, 4} ``

In the above example, `setA` and `setB` are two sets ,and performs intersection operation on the sets.

By default, Python does not support performing direct intersection on lists. But with a little tweaking, we can perform intersection on lists as well.

## Get List Intersection in Python With the `&` Operator

The `&` operator, as discussed above, cannot be used with lists. So, we have to change our lists to sets using .

``list1 = [1, 2, 3, 4, 5] list2 = [0, 2, 4, 6]  set1 = set(list1) set2 = set(list2)  set3 = set1 & set2 list3 = list(set3)  print(list3) ``

Output:

``[2, 4] ``

The `set()` function converts a list to a set. The `&` operation returns a set that contains all the common elements in both sets. As we know, we have to perform this operation on lists rather than on sets. So, we have to convert this set into a list using the `list()` function.

## Get List Intersection in Python With the `intersection()` Method

The of the `set` class is another way to perform intersection on sets in Python. Similar to the `&` operator, it is also limited to just sets. But by converting the `list1` into a set, we can also use `intersection()` with `list1`.

``list1 = [1, 2, 3, 4, 5] list2 = [0, 2, 4, 6]  set1 = set(list1) set2 = set(list2)  set3 = set(list1).intersection(list2) list3 = list(set3)  print(list3) ``

Output:

``[2, 4] ``

The `intersection()` method also returns a set of all the common elements. So, we have to convert it into a list using the `list()` function.

### Get List Intersection in Python With the List Comprehensions

Both methods discussed above are designed to work with sets rather than lists. As we all know that a set cannot have recurring values, and its elements are unsorted, these functions don’t work well if we have recurring values in our lists or we want to retain the order in our lists.

The drawbacks of the previous two methods are demonstrated in this coding example.

``list1 = [1, 2, 3, 2, 4, 5] list2 = [0, 2, 2, 4, 6]  setintersection = list(set(list1) & set(list2)) intersectionmethod = list(set(list1).intersection(list2))  print("The result of set intersection :") print(setintersection) print("The result of intersection() method :") print(intersectionmethod) ``

Output:

``The result of set intersection : [2, 4] The result of intersection() method : [2, 4] ``

As shown above, we expect `[2, 2, 4]` as the right result but only get `[2, 4]`.

is another way of performing the `AND` operation on lists in Python. It can handle recurring values and also keep the order of elements, which is not kept in the above two methods.

``#Solution 2 Using list comprehensions list1 = [1, 2, 3, 2, 4, 5] list2 = [0, 2, 2, 4, 6] list3 = [x for x in list1 if x in list2] #all the x values that are in A, if the X value is in B print(list3) ``

Output:

``[2, 2, 4] ``