python - Removing nan values from an array

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Top 5 Answer for python - Removing nan values from an array

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If you're using numpy for your arrays, you can also use

x = x[numpy.logical_not(numpy.isnan(x))] 


x = x[~numpy.isnan(x)] 

[Thanks to chbrown for the added shorthand]


The inner function, numpy.isnan returns a boolean/logical array which has the value True everywhere that x is not-a-number. As we want the opposite, we use the logical-not operator, ~ to get an array with Trues everywhere that x is a valid number.

Lastly we use this logical array to index into the original array x, to retrieve just the non-NaN values.

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filter(lambda v: v==v, x) 

works both for lists and numpy array since v!=v only for NaN

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Try this:

import math print [value for value in x if not math.isnan(value)] 

For more, read on List Comprehensions.

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For me the answer by @jmetz didn't work, however using pandas isnull() did.

x = x[~pd.isnull(x)] 
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As shown by others


works. But it will throw an error if the numpy dtype is not a native data type, for example if it is object. In that case you can use pandas.

x[~pandas.isna(x)] or x[~pandas.isnull(x)] 

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